The graph shows two lines. What is the solution to the system?
A(1, 2)
B(3, 0)
C(2, 3)
D(0, 1)
Explanation
📌 The solution is where the lines intersect = (1, 2). Verify: y = x + 1 → 2 = 1 + 1 ✓ y = −x + 3 → 2 = −1 + 3 ✓
Question 3 of 10
TEKS 2A-2HEasy Calc Word Diagram
What is the slope of the line shown?
A−1
B1
C1/2
D2
Explanation
📌 slope = rise/run = (3-(-1))/(2-(-2)) = 4/4 = 1
💡 Positive slope → line goes UP from left to right.
Question 4 of 10
TEKS 2A-2HMedium Calc Word Diagram
Which line has a negative slope?
ABoth
BNeither
CB
DA
Explanation
📌 Negative slope = line goes DOWN from left to right (↘). Positive slope = line goes UP from left to right (↗). Graph B has negative slope.
Question 5 of 10
TEKS 4A-4CMedium Calc Word Diagram
The scatter plot shows the relationship between hours studied and test scores. What type of correlation is shown?
APositive correlation
BNegative correlation
CCannot determine
DNo correlation
Explanation
📌 Points trend upward from left to right → positive correlation. As hours studied increases, test score increases. The trend line slopes upward → positive relationship.
Question 6 of 10
TEKS 5A-5CMedium Calc Word Diagram
The system of equations is graphed below. How many solutions does it have?
AOne solution
BTwo solutions
CInfinitely many solutions
DNo solution
Explanation
📌 The lines are parallel (same slope, different y-intercepts). Parallel lines NEVER intersect → NO solution.
Systems with no solution are called 'inconsistent.'
Question 7 of 10
TEKS 1A-1GEasy Calc Word Diagram
A cell phone plan charges $30 per month plus $0.10 per text. Which equation represents the monthly cost C for t texts?
AC = 30 + 0.10t
BC = 30.10t
CC = 0.10(30 + t)
DC = 30t + 0.10
Explanation
📌 Fixed cost = $30 (base monthly charge) Variable cost = $0.10 per text = 0.10t Total: C = 30 + 0.10t
💡 This is a linear equation in slope-intercept form: y = mx + b where m = 0.10 and b = 30.
Question 8 of 10
TEKS 5A-5CHard Calc Word
Solve: 2x + 3y = 13, 4x − y = 5
A(4, 1)
B(3, 2)
C(1, 4)
D(2, 3)
Explanation
📌 From eq2: y = 4x − 5 Substitute: 2x + 3(4x−5) = 13 → 2x + 12x − 15 = 13 → 14x = 28 → x = 2 y = 4(2) − 5 = 3