SAT Math — Quick Drill
Quick Drill · 10 Questions · 15 min
15:00Exit
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Question 1 of 10
TEKS ALGEasy

Solve for x:

7x + 10 = 94

A12
B16
C8
D7
Explanation
Subtract 10 from both sides: 7x = 84. Then divide both sides by 7: x = 12.
Question 2 of 10
TEKS ALGEasy

Solve for x:

9x + 5 = 59

A11
B6
C5
D3
Explanation
Subtract 5 from both sides: 9x = 54. Then divide both sides by 9: x = 6.
Question 3 of 10
TEKS ALGEasy

Solve for x:

4x + 16 = 32

A1
B4
C8
D5
Explanation
Subtract 16 from both sides: 4x = 16. Then divide both sides by 4: x = 4.
Question 4 of 10
TEKS GEOEasy Diagram
The circle shown has a radius of 7. What is the area of the circle, in terms of π? r = 7
A49π
B14π
C
D98π
Explanation
Area = πr² = π(7)² = 49π. (Don't confuse with circumference 2πr.)
Question 5 of 10
TEKS GEOEasy Diagram
The circle shown has a radius of 12. What is the area of the circle, in terms of π? r = 12
A144π
B24π
C12π
D288π
Explanation
Area = πr² = π(12)² = 144π. (Don't confuse with circumference 2πr.)
Question 6 of 10
TEKS ALGEasy

Solve for x:

2x + 12 = 22

A6
B0
C2
D5
Explanation
Subtract 12 from both sides: 2x = 10. Then divide both sides by 2: x = 5.
Question 7 of 10
TEKS GEOEasy Diagram
The circle shown has a radius of 6. What is the area of the circle, in terms of π? r = 6
A72π
B12π
C36π
D
Explanation
Area = πr² = π(6)² = 36π. (Don't confuse with circumference 2πr.)
Question 8 of 10
TEKS GEOEasy Diagram
The circle shown has a radius of 3. What is the area of the circle, in terms of π? r = 3
A18π
B
C
D
Explanation
Area = πr² = π(3)² = 9π. (Don't confuse with circumference 2πr.)
Question 9 of 10
TEKS GEOEasy Diagram
The circle shown has a radius of 5. What is the area of the circle, in terms of π? r = 5
A10π
B
C25π
D50π
Explanation
Area = πr² = π(5)² = 25π. (Don't confuse with circumference 2πr.)
Question 10 of 10
TEKS GEOEasy Diagram
The circle shown has a radius of 11. What is the area of the circle, in terms of π? r = 11
A121π
B242π
C22π
D11π
Explanation
Area = πr² = π(11)² = 121π. (Don't confuse with circumference 2πr.)

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